#!/usr/bin/python
import cgi
import cgitb
from spider import *
cgitb.enable()
def validate_input(uri):
""" The HTML parser apparently accepts any URI without the http part, so if the user inputs such a URI we have to strip it off. Also we need to check if this particular URI exists """
if uri.find('http://') != -1:
trail = uri[7:].find('/')
if trail != -1:
site = uri[7:trail+7]
else:
site = uri[7:]
elif uri.find('https://') != -1:
trail = uri[8:].find('/')
if trail != -1:
site = uri[8:trail+8]
else:
site = uri[8:]
else:
"""Find the site URI without the protocol or the trailing path """
trail = uri.find('/')
if trail != -1:
site = uri[:trail]
else:
site = uri
return site
def print_table(list):
print "
"
for val in list:
print """
"""
print """
"""
print """
"""
print """
By """ % (val[3])
print """%s """ % (val[2])
if int(val[1]) == 0:
print "All Rights Reserved"
else :
""" The following snippet of code adds the license icons one-by-one as required to indicate the license the Flickr photos come with. Note that the image icons are stored in dig space"""
#Print the generic CC icons
print """Has License """
if int(val[1]) == 1:
print """ """
attribution_xhtml = """
Creative Commons Attribution License Violations Validator for Flickr Images
"""
form = cgi.FieldStorage()
uri = form.getvalue("uri" , "")
print """
Enter the URI of a page which has embedded Flickr images. The validator will indicate if you have not properly attributed the owner of those images (if the images are under a Creative Commons Attribution license). You can use the Attribution XHTML provided on the page to correct your errors.
"""
if uri != "": #somebody has put in a value for the blog URI
#TODO: Check whether it's a valid URI
result = crawl(form.getvalue("uri"))
attr_given = result[1]
attr_not_given = result[2]
nameless = result[3]
n_attr_given = len(attr_given)
n_attr_not_given = len(attr_not_given)
n_nameless = len(nameless)
print """
"""
print """Results for the page """ % (uri)
print """%s. """ % (uri)
if int(n_attr_not_given) == 1:
print """
Found an attribution license violation for the following image.
"""
if int(val[1]) == 1:
print """ 
"""
attribution_xhtml = """""" % (val[0],val[3],val[2])
if int(val[1]) == 2:
print """ 
"""
attribution_xhtml = """""" % (val[0],val[3],val[2])
if int(val[1]) == 4:
print """